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-5x^2+24x-27=0
a = -5; b = 24; c = -27;
Δ = b2-4ac
Δ = 242-4·(-5)·(-27)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6}{2*-5}=\frac{-30}{-10} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6}{2*-5}=\frac{-18}{-10} =1+4/5 $
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